Arrays
are very important for working with different types of data in JavaScript.
Sometimes we need to work with only even or odd numbers from an array as per
our needs. For example, we have an array of numbers and we need to separate
even and odd numbers from this array. In today's blog, we will discuss in
detail how to easily extract even or odd numbers from an array, so let's get
started –
Problem:
Extract even and odd numbers from an array?
Code
and explanation:
const numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
const evenNumbers = numbers.filter(num => num % 2 === 0);
const oddNumbers = numbers.filter(num => num % 2 !== 0);
console.log("Even numbers:", evenNumbers);
console.log("Odd numbers:", oddNumbers);
Code
explanation:
- First, an array named numbers is created where some even and odd numbers are kept.
- Then we create a new array named evenNumbers, where only those numbers are selected using the numbers.filter() function which satisfies the condition num % 2 === 0. Here num % 2 === 0 means that the number is divisible by 2, i.e. even.
- Similarly, another new array named oddNumbers is created. Here, using the numbers.filter() function, only those numbers are selected that satisfy the condition num % 2 !== 0. Here num % 2 !== 0 means that the number is not divisible by 2, i.e. odd.
- Finally, using console.log(), even and odd numbers are displayed separately.
Output
Even numbers: [2, 4, 6, 8, 10]
Odd numbers: [1, 3, 5, 7, 9]
Method
2 –
const numbers = [11, 22, 33, 44, 55, 66, 77, 88, 99, 100];
let evenNumbers = [];
let oddNumbers = [];
for (let i = 0; i < numbers.length; i++) {
if (numbers[i] % 2 === 0) {
evenNumbers.push(numbers[i]);
} else {
oddNumbers.push(numbers[i]);
}
}
console.log("Even numbers:", evenNumbers);
console.log("Odd numbers:", oddNumbers);
Explanation
of the code:
- First, an array named numbers is created in which some numbers are stored.
- Two empty arrays named evenNumbers and oddNumbers are created, where even and odd numbers will be stored separately.
- Then, each element of the numbers array is checked using a for loop.
- Using the condition if (numbers[i] % 2 === 0) we check whether the current number is divisible by 2 or not. If it is divisible, then the number is even and it is added to the evenNumbers array. Otherwise, i.e. it will enter the else part and if the number is odd, it will be added to the oddNumbers array.
- Finally, using console.log(), even and odd numbers are displayed separately.
Output
Even numbers: [22, 44, 66, 88, 100]
Odd numbers: [11, 33, 55, 77, 99]
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